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Poll
Question: Winner?
Murray/Becker in 2 - 2 (18.2%)
Murray/Becker in 3 - 7 (63.6%)
Mahut/Benneteau in 2 - 1 (9.1%)
Mahut/Benneteau in 3 - 0 (0%)
Retirement - 1 (9.1%)
Total Voters: 11

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Murray/Becker v Mahut/Benneteau

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Allan
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It's 2013!

Murray/Becker v Mahut/Benneteau « on: January 16, 2007, 07:28 PM »
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Jamie should have his own match threads when he's not playing with Andy  w00t

Tricky round for the first time pairing of Jamie and Becker but they could win they play to their potential.
Benneteau (ranked 71; career high of 35) and Mahut (ranked 80; career high of 25) have been successful together. They have reached the quarters of Roland Garros last year and the quarters of the US Open the year before.

This match will be played on Thursday.
[ Last edit by Allan January 16, 2007, 07:30 PM ] IP Logged
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John McEnroe
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Re: Murray/Becker v Mahut/Benneteau « Reply #1 on: January 16, 2007, 07:28 PM »
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They can do it. Becker is really on-form.
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rochelle
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Andy and Jamie

Re: Murray/Becker v Mahut/Benneteau « Reply #2 on: January 16, 2007, 07:42 PM »
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They can do it. Becker is really on-form.

yeah he is ... so is Jamie
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John McEnroe
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Re: Murray/Becker v Mahut/Benneteau « Reply #3 on: January 16, 2007, 07:44 PM »
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So is Mahut, but let's ignore that fact. Benneteau is not a threat at all.
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rochelle
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Andy and Jamie

Re: Murray/Becker v Mahut/Benneteau « Reply #4 on: January 16, 2007, 07:57 PM »
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So is Mahut, but let's ignore that fact.

agreed... lets pretend he doesnt exist
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Allan
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It's 2013!

Re: Murray/Becker v Mahut/Benneteau « Reply #5 on: January 16, 2007, 08:02 PM »
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Does anyone know if it's best of 3 or best of 5 sets?
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rochelle
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Andy and Jamie

Re: Murray/Becker v Mahut/Benneteau « Reply #6 on: January 16, 2007, 08:10 PM »
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Does anyone know if it's best of 3 or best of 5 sets?

not sure ... best of 3 i think though... prob wrong
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top_spin
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Re: Murray/Becker v Mahut/Benneteau « Reply #7 on: January 16, 2007, 09:08 PM »
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Should be best of 3. Very interesting pairing. Think
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Sir Panda
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Re: Murray/Becker v Mahut/Benneteau « Reply #8 on: January 16, 2007, 09:10 PM »
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Benneteau crumbled today of heat exhaustion I think. Don't imagine this will be too difficult.

I think only Wimbledon has best of 5 for doubles matches.
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Neil
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Re: Murray/Becker v Mahut/Benneteau « Reply #9 on: January 16, 2007, 11:36 PM »
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Murray is the highest ranked doubles player among them i think. GO MURRAY AND BECKER! I said in 3.
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Re: Murray/Becker v Mahut/Benneteau « Reply #10 on: January 17, 2007, 12:07 AM »
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I would say they have a good chance. Go Jamie!
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Allan
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It's 2013!

Re: Murray/Becker v Mahut/Benneteau « Reply #11 on: January 17, 2007, 08:09 AM »
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This match is 3rd on Court 15 tomorrow (Thursday)
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XCW4EVA
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Re: Murray/Becker v Mahut/Benneteau « Reply #12 on: January 17, 2007, 02:03 PM »
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Aucks/Hess won today btw, i sed Becker and Murray in three mainly coz Becker/Murray have a doubles specialist in there team
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Neil
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Re: Murray/Becker v Mahut/Benneteau « Reply #13 on: January 17, 2007, 02:37 PM »
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It's best of 3 sets. So if your reason is that Murray is the doubles specialist, u perhaps mean in 2?
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ljsmall
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Re: Murray/Becker v Mahut/Benneteau « Reply #14 on: January 17, 2007, 02:42 PM »
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Murray/Becker in 3. It's a tough draw for a first round but they can do it.
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